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classification
Title: 'is' does not work for methods
Type: Stage:
Components: Interpreter Core Versions: Python 2.4
process
Status: closed Resolution: duplicate
Dependencies: Superseder:
Assigned To: Nosy List: collinwinter
Priority: normal Keywords:

Created on 2006-01-09 10:08 by collinwinter, last changed 2022-04-11 14:56 by admin. This issue is now closed.

Messages (1)
msg27260 - (view) Author: Collin Winter (collinwinter) * (Python committer) Date: 2006-01-09 10:08
As of Python 2.4.2 (gcc 3.3.6, linux 2.6.13), the 'is'
comparison operator does not work for instancemethods
or classmethods (though it does work for
staticmethods). For example:

"""
>>> class A(object):
...   def foo(self): pass
...
>>> id(A.foo) == id(A.foo)
True
>>> A.foo is A.foo
False
>>>
>>> a = A()
>>> id(a.foo) == id(a.foo)
True
>>> a.foo is a.foo
False
"""

This example is applicable to old-style classes and
new-style classes, though things get more complicated
in the case of built-in types:

"""
>>> d = dict()
>>> id(d.update) == id(d.update)
True
>>> d.update is d.update
False
>>>
>>> id(dict.update) == id(dict.update)
True
>>> dict.update is dict.update
True
"""

However, using the classmethod 'fromkeys':

"""
>>> d = dict()
>>> id(d.fromkeys) == id(d.fromkeys)
True
>>> d.fromkeys is d.fromkeys
False
>>>
>>> id(dict.fromkeys) == id(dict.fromkeys)
True
>>> dict.fromkeys is dict.fromkeys
False
"""
History
Date User Action Args
2022-04-11 14:56:14adminsetgithub: 42779
2006-01-09 10:08:55collinwintercreate