Why (1.16 * 100) is not the same than (1.16 * 10 * 10)?

I tried 1.16*100. also and it is = 115.99999999; but if I 
do 1.16*10*10 I get 116.

Thanks....

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The answer to your question can be found in the Python 
tutorial, and has nothing to do with regular expressions:

http://www.python.org/doc/tut/node14.html

Please don't use the bug tracker to ask for help in the 
future; I suggest asking on comp.lang.python (for other 
help forums, see www.python.org).

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I'sorry, but I don't agree...
Even 3.13 (3.1299999999999999) * 100 is 313 = like 
3.13*10*10 (3.13*100=3.13*10*10)
In this case 1.16*100 <> 1.16*10*10
Sorry again, but it is a huge difference when you do int
(1.16*100)=115  or you do int(1.16*10*10)=116
Thanks...

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This is not a bug.

Binary floating point cannot represent decimal fractions exactly,
so some rounding always occurs (even in Python 1.5.2).

What changed is that Python 2.0 shows more precision than before
in certain circumstances (repr() and the interactive prompt). 

You can use str() or print to get the old, rounded output: 

>>> print 0.1+0.1
0.2
>>>

Follow the link for more information:

http://www.python.org/doc/2.2.1/tut/node14.html

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