In the docs to Python 2.3.4 (#53, May 25 2004,
21:17:02), Section 4.6 of the Python Tutorial says:

The execution of a function introduces a new symbol
table used for the local variables of the function.
More precisely, all variable assignments in a function
store the value in the local symbol table; whereas
variable 
references first look in the local symbol table, then
in the global symbol table, and then in the table of
built-in names. Thus, global variables cannot be
directly assigned a value within a function (unless
named in a
 global statement), although they may be referenced. 

This doesn't make it clear that in the following sort
of case, the nested def can 'see' the varriables in the
topmost function:

>>> spam = 1
>>> def foo():
	spam = 2
	ham = 3
	def bar():
		print spam, ham
	bar()

	
>>> foo()
2 3

I suggest the following ammendment:

. . . whereas variable references first look in the
local symbol table, then in the local scope of the
enclosing function defs (if any), then in the global
symbol table, . . .

Thanks,

Brian vdB

Logged In: YES 
user_id=1015686

Hi,

I'm new to SF. I meant the e.g. to read like:

>>> spam = 1
>>> def foo():
....spam = 2
....ham = 3
....def bar():
........print spam, ham
....bar()

>>> foo()
2 3

(where '.' are spaces.)

Thanks,

brian

Fixed in r60158.